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4m^2-27m-49=0
a = 4; b = -27; c = -49;
Δ = b2-4ac
Δ = -272-4·4·(-49)
Δ = 1513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{1513}}{2*4}=\frac{27-\sqrt{1513}}{8} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{1513}}{2*4}=\frac{27+\sqrt{1513}}{8} $
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